Question

Megan is twice as old as anne. six years ago, megan was 4 times as old as anne. how old are they now?

Answer 1

let megan's age is x and anne's is y

x = 2y

x-6 = 4(y-6)

2y-6 = 4y -24

2y = 18

y = 9

x = 18

Answer 2

Megan and Anne are 18 years and 9 years old respectively

Explanation:

Let Megan's age be M and Anne's A

M = 2A

six years ago

Megan's age then was M - 6

Anne's age then was A - 6

Since megan was 4 times as old as anne

M - 6 = 4(A - 6)

M - 6 = 4A -24

M = 4A - 18

since M = 2A

2A = 4A - 18

4A - 2A = 18

2A = 18

A = 9

M = 2A

M = 18

Megan and Anne are 18 years and 9 years old respectively.