Question

Water's heat of fusion is 80. cal/g , its specific heat is 1.0calg⋅∘C, and its heat of vaporization is 540 cal/g .

A canister is filled with 350 g of ice and 100. g of liquid water, both at 0 ∘C . The canister is placed in an oven until all the H2O has boiled off and the canister is empty. How much energy in calories was absorbed?

Answer 1

Q1=(330g)*(80cal/g)=26,400cal

Q2=(430cal)*(1cal/(g-c)*(100c=43,000cal

Q3=(430g)*(540 cal/g)= 232,200cal

Total heated absorbed is

Q1+Q2+Q3= 301,600 or 301.6 kcal

Step-by-step explanation:

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