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in the basketball game Jake made 23 baskets each of the baskets was worth either two or three points and Jake scored a total of 53 points how many two-point and three-point baskets did Jake make

User Darvex
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2 Answers

3 votes

Answer:

(16,7) is the answer

2 votes
Greetings!

Let x represent the number of 2 pointers made.
Let y represent the number of 3 pointers made.

We have to create a system of equations to solve this problem:

\left \{ {{x+y=23} \atop {2x+3y=53}} \right.

Isolate for
x in Equation #1:

x+y=23


x=23-y

Substitute the new Equation #1 into Equation #2:

2x+3y=53


2(23-y)+3y=53

Solve for
y :

2(23-y)+3y=53

Distribute the Parenthesis:

46-2y+3y=53

Combine like terms:

46+y=53

Add -46 to both sides:

(46+y)+(-46)=(53)+(-46)


y=7

Substitute this value into Equation #1:

x+y=23


x+(7)=23

Add -7 to both sides:

(x+7)+(-7)=(23)+(-7)


x=16

The Solution Is:

\boxed{(16,7)}

Jake made 16 two-pointers and 7 three-pointers!

I hope this helped!
-Benjamin


User Natan Braslavski
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