Question

I need help on a question

Answer 1

For this case we can do the following:

a+ b= 15

`\cos 60=(a)/(x),\sin 60=(y)/(x)`
`\cos 30=(b)/(z),\sin 30=(y)/(z)`
`\tan 60=(y)/(a),\tan 30=(y)/(b)`
`(\tan 60)/(\tan 30)=(b)/(a)`

b=3a

Replacing in the first equation we got:

a + 3a = 15

4a = 15

a = 15/4

b= 45/4

Then we can find the value of y on the following way:

y= a *tan 60 = 15/4 * tan 60

`y=\frac{15\sqrt[]{3}}{4}`