Question

Eva bought popcorn, candy and a drink at the movies. The popcorn was three times as expensive as the candy and the drink was twice as expensive as the candy. Eva spent a total of $10.50. What is the price of the candy?

Answer 1

Given: Eva bought popcorn, candy, and a drink such that

• The popcorn was ,three times, as expensive as the candy.

,

• The drink was ,twice ,as expensive as the candy.

Required: To determine the cost of the candy.

This is explained thus:

Let the cost of the candy be x.

Therefore, the cost of the popcorn is 3x.

Also, the cost of the drink is 2x.

Since she spent a total of $10.50, we can determine the cost of the candy thus:

`\begin{gathered} Cost(popcorn)+Cost(candy)+Cost(drink)=10.50 \\ 3x+x+2x=10.50 \\ 6x=10.50 \\ \text{ Divide both sides by 6} \\ (6x)/(6)=(10.50)/(6) \\ x=1.75 \end{gathered}`

Hence, the cost of the candy is $1.75.