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Bacteria in a pond multiplies as shown in the table. If a fungus on a tree decays at half that rate, what is the rate of decay (round to the nearest integer)?

thanks!

Bacteria in a pond multiplies as shown in the table. If a fungus on a tree decays-example-1
User Tuya
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2 Answers

7 votes

Answer:

20%

Explanation:

Population growth formula:


P = P_0 * e^(rt)

where P is the total population after time t,
P_0</p><p> is the starting population, r is the rate of growth and t is the time in hours

Solving for r:


(ln((P)/(P_0)))/(t)=r

and replacing with data:

P = 22.781


P_0 = 4.5 (taking hour 2 as initial time)

t = 4 hours (time elapsed between initial time and time the population reach P)


r=\frac{ln((22.781)/(4.5)){4}

r = 0.4, that is equivalent to 40%

Then, fungus decay rate is 40%/2 = 20%

User Hkchengrex
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5 votes
Using the formula, y=a(1=r)^x to solve for the growth rate and you find that the growth rate for the bacteria is 50%. Once this information is found, you can determine that a fungus decay at half that rate will be 25%.
User Nathan Wiles
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