62.1k views
2 votes
A dresser measures 3.5 feet tall and 6.25 feet long. To the nearest tenth of a foot, what is the diagonal length of the dresser?

User Svenskmand
by
8.1k points

1 Answer

6 votes
A^2 + B^2 = C^2 3.5^2 +6.25^2 = 51.31 (don’t forget to square root) the square root of 51.31 = 7.16 feet
User Phi
by
8.7k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories