Question

A dresser measures 3.5 feet tall and 6.25 feet long. To the nearest tenth of a foot, what is the diagonal length of the dresser?

Answer 1

A^2 + B^2 = C^2 3.5^2 +6.25^2 = 51.31 (don’t forget to square root) the square root of 51.31 = 7.16 feet