Question

Pre-cal. Need last part of the answer

Answer 1

`\bf f(x)=\cfrac{3}{x+6}\qquad \qquad \cfrac{f(a+h)-f(a)}{h}\implies \cfrac{(3)/(a+h+6)-(3)/(a+6)}{h} \\\\\\ \textit{so our LCD will then be }(a+h+6)(a+6)\textit{ for the numerator} \\\\\\ \cfrac{([3(a+6)]~~-~~[3(a+h+6)])/((a+h+6)(a+6))}{h}\implies \cfrac{([3a+18]~~-~~[3a+3h+18])/((a+h+6)(a+6))}{h}`


`\bf \cfrac{\frac{\underline{3a+18}~~\underline{-3a}-3h\underline{-18}}{(a+h+6)(a+6)}}{h}\implies \cfrac{(-3h)/((a+h+6)(a+6))}{h}\implies \cfrac{(-3h)/((a+h+6)(a+6))}{(h)/(1)} \\\\\\ \cfrac{-3h}{(a+h+6)(a+6)}\cdot \cfrac{1}{h}\implies \cfrac{-3\underline{h}}{\underline{h}(a+h+6)(a+6)} \\\\\\ \cfrac{-3}{(a+h+6)(a+6)}`