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Find the values of p,q, and r (px + q) (2x + 5) = 6x² + 11x + r please show your work .
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Find the values of p,q, and r (px + q) (2x + 5) = 6x² + 11x + r please show your work .
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Jul 25, 2018
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Find the values of p,q, and r
(px + q) (2x + 5) = 6x² + 11x + r
please show your work .
Mathematics
high-school
Billyjov
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Billyjov
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so hmmmm recall FOIL.
on a two binomial set
(ax+b)(cx+d), you get a trinomial that is
(a*c)x² + [(ax*d) + (cx*b)] x +(b*d).
that said, then
and "r" of course, is just (q*5), and surely you know what that is.
Sam Skuce
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Jul 28, 2018
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Sam Skuce
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(px+q)(2x+5)=6x^2+11x+r
2px² + (5p + 2q)x + 5q = 6x² + 11x + r
Start with the x² coefficients:
2px² = 6x²
2p = 6
p = 3
Next, the x coefficients:
(5p + 2q)x = 11x
( (5)(3) + 2q) = 11
15 + 2q = 11
2q = -4
q = -2
Next, the constant terms:
5q = r
5(-2) = r
r = -10
Thus,
p = 3, q = -2, r = -10
Gyula
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Jul 31, 2018
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Gyula
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