How many moles of potassium hydroxide (KOH) are needed to completely neutralize 1.56 mol phosphoric acid (H3PO4)?

Question

asked Nov 19, 2018 176k views

2 Answers

Kirogasa · Answer 1 · 2018-11-22T20:00:56+0000

Answer : The number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.

Explanation :

The balanced chemical reaction will be:

$3KOH+H_3PO_4\rightarrow K_3PO_4+3H_2O$

From the balanced chemical reaction we conclude that,

As, 1 mole of
H_3PO_4 neutralizes 3 moles of KOH

So, 1.56 mole of
H_3PO_4 neutralizes
1.56* 3=4.68 moles of KOH

Thus, the number of moles of potassium hydroxide (KOH) are needed to completely neutralize are 4.68 moles.