101 101 (3)/(4) + 33 (1)/(4) + 5 (1)/(4)

Question

101

`101 (3)/(4) + 33 (1)/(4) + 5 (1)/(4)`

Answer 1

first off, we convert the mixed fractions to "improper", and proceed getting their LCD from there, let's do so,


`\bf 101(3)/(4)+33(1)/(4)+5(1)/(4)\\\\ -------------------------------\\\\ \stackrel{mixed}{101(3)/(4)}\implies \cfrac{101\cdot 4+3}{4}\implies \stackrel{improper}{\cfrac{407}{4}} \\\\\\ \stackrel{mixed}{33(1)/(4)}\implies \cfrac{33\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{133}{4}} \\\\\\ \stackrel{mixed}{5(1)/(4)}\implies \cfrac{5\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{21}{4}}\\\\ -------------------------------`


`\bf \cfrac{407}{4}+\cfrac{133}{4}+\cfrac{21}{4}\impliedby \textit{clearly their LCD is 4}\implies \cfrac{407+133+21}{4} \\\\\\ \cfrac{561}{4}\implies 140(1)/(4)`