Question

Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a radius of 4 feet and a height of 4 feet. Container B has aradius of 2 feet and a height of 14 feet. Container A is full of water and the water ispumped into Container B until Conainter B is completely full.To the nearest tenth, what is the percent of Container A that is empty after thepumping is complete?

Answer 1

we know that

The volume of a cylinder is equal to

V=pi r^2 h

where

r is the radius of cylinder

h is the height of cylinder

Step 1

Find the volume of cylinder A

we have

r=4 ft

h=4 ft

substitute in the formula

V=pi(4^2)(4)

V=64pi ft^3

Step 2

Find the volume of cylinder B

we have

r=2 ft

h=14 ft

substitute

V=pi(2^2)(14)

V=56pi ft^3

step 3

Find the difference of volume cylinder A and volume cylinder B

so

V=64pi-56pi

V=8pi ft^3

step 4

Find the percentage of container A that is empty

we have that

in container A

8pi ft^3 -------> is water

56pi ft3 -----> is empty

so

If 64pi ft^3 ----------> 100%

then

56pi ft^3 -------> x

Applying rule of three

x=56pi(100)/64pi

x=87.5%

the answer is

the percent of container A that is empty is 87.5%