Question

In a random sample of 70 people, it was found that 44 of them were fans of the New York Yankees. What is the margin of error for the true proportion of all individuals who are fans of the New York Yankees?

Answer 1

It's been a while since I learned about margin of error. I'm pretty sure you solve it by dividing 44/70 which gives you about 0.63, but that doesn't seem right :|

Answer 2

The margin of error is 0.0577.

Explanation:

The margin of error can be found by :

`z*\sqrt{(p(1-p))/(n)}`

Where

z gives the values for selected confidence level but it is not given.

p is the sample proportion

n is the sample size

As z is not given, so we will solve for the :

`\sqrt{(p(1-p))/(n)}`

We have p =
`44/70`

n = 70

Putting these values in the above formula:

`\sqrt{(44/70(1-44/70))/(70)}`

=
`√(0.0033350)`

= 0.0577

Therefore, the margin of error is 0.0577.