Question

Can you tell me if the answer I have gotten is correct

Answer 1

In order to calculate the horizontal distance the ball will travel after falling off the table, first let's calculate the time the ball will be falling, using the formula below and considering the vertical movement:

`\begin{gathered} \Delta S=V_0\cdot t+a\cdot(t^2)/(2) \\ 1=0+9.81\cdot(t^2)/(2) \\ 1=4.905t^2 \\ t^2=(1)/(4.905) \\ t=0.45 \end{gathered}`

So the ball was falling for 0.45 seconds. Let's use this time to calculate the horizontal displacement when the ball started falling:

`\begin{gathered} \Delta S=V\cdot t \\ \Delta S=1.4\cdot0.45 \\ \Delta S=0.63\text{ meters} \end{gathered}`

So the distance is 0.63 meters.