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1 vote
Solve this quadratic equation.
x^2 + 5x + 3 = 0

2 Answers

5 votes

Answer:

ALVS verified

Explanation:

x=5±√37/2

User Andreas Baus
by
7.1k points
2 votes
Hi there!
The question gives us the quadratic equation
x^(2) +5x+3=0, and it tells us to solve it using the quadratic formula, which goes as
x = (-b \pm √(b^2 - 4ac) )/(2a). However, we must first find the values of a, b, and c. The official quadratic equation goes as
ax^2+bx+c, which matches the format of the given quadratic equation. Hence, the value of a would be 1, the value of b would be 5, and the value of c would be 3. Now, just plug it back into the quadratic equation and simplify to get the zeros of the equation.

x = (-b \pm √(b^2 - 4ac) )/(2a)

x = (-(5) \pm √((5)^2 - 4(1)(3)) )/(2(1))

x = (-5 \pm √(25 - 12) )/(2)

x = (-5 \pm √(13) )/(2)

x = (-5 \pm 3.61 )/(2)

x = (-5 + 3.61 )/(2), x = (-5 - 3.61 )/(2)

x=-0.695 \ \textgreater \ \ \textgreater \ -0.7, x= -4.305 \ \textgreater \ \ \textgreater \ x=-4.31
Therefore, the solutions to the quadratic equation
x^(2) +5x+3=0 are x = -0.7 and x = -4.31. Hope this helped and have a phenomenal day!

User Fusilli Jerry
by
8.1k points

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