Answer:

Explanation:
The zeroes of a function are the x values of the points at which the graph intersects the x-axis. All points on the x-axis have a y-value of 0, therefore, we need to find out which values of x can be plugged in to have the result be 0. This function is already factored out. So, for each expression, find which input of x makes the result equal 0.
1) So, start with 2x + 3. Set it equal to 0 and solve for x:

Therefore,
is one of the zeroes.
2) Next, set x-5 equal to 0 and solve, too:

Therefore, 5 is one of the zeroes.
3) Thus, the zeroes are
and 5.