Question

A ball was rolling downhill at 2 m/s. After 5s, it was rolling at 90 m/s. What is its acceleration?

Answer 1

17.6 m/s²

Step-by-step explanation:

Given:

`v_(f)` = 90 m/s (final velocity)

`v_(i)` = 2 m/s (initial velocity)

Δt = 5s (change in time)

The formula for acceleration is:

`a_(avg)` = Δv / Δt

We can find Δv by doing

Δv =
`v_(f)` -
`v_(i)`

Replace the values

Δv = 90m/s - 2m/s

Δv= 88m/s

Using the equation from earlier, we can find the acceleration by dividing the average velocity by time.

`a_(avg)` = Δv / Δt

`a_(avg)` =
`(88m/s)/(5/s)`

acceleration = 17.6
`m/s^(2)`