Question

Solve the system by the elimination method. 3x - 2y - 7 = 0 5x + y - 3 = 0 To eliminate y, the LCM is 2. Which of the following is the resulting equations? 3x - 2y - 7 = 0 5x + y - 3 = 0 3x - 2y - 7 = 0 -10x - 2y + 6 = 0 3x - 2y - 7 = 0 10x + 2y - 6 = 0

Answer 1

`x=1` and
`y=-2`.

Explanation:

We have been given a system of equations. We are asked to simplify our given system by the elimination method.

`3x-2y-7=0...(1)`

`5x+y-3=0...(2)`

First of all, we will multiply equation (2) by 2 as shown below:

`2*5x+2*y-2*3=0...(2)`

`10x+2y-6=0...(2)`

Upon adding equation (1) and (2), we will get:

`(3x-2y-7=0)+(10x+2y-6=0)\rightarrow 3x+10x-2y+2y-7-6=0`

`13x-13=0`

`13x-13+13=0+13`

`13x=13`

`(13x)/(13)=(13)/(13)`

`x=1`

Upon substituting
`x=1` in equation (2), we will get:

`5*1+y-3=0`

`5+y-3=0`

`2+y=0`

`2-2+y=0-2`

`y=-2`

Therefore, the solution for our given system of equation is
`x=1` and
`y=-2`.

Answer 2

Next time, please share your system of linear equations by typing only one equation per line:

3x - 2y - 7 = 0 5x + y - 3 = 0 NO

3x - 2y - 7 = 0
5x + y - 3 = 0 YES

Mult. the 2nd equation by 2 so as to obtain 2y, which will be cancelled out by - 2y in the first equation:

3x - 2y - 7 = 0
2(5x + y - 3 = 0)

Then:

3x - 2y - 7 = 0
10x +2y - 6 = 0
----------------------
13x - 13 = 0, so that x = 1. Find y by subbing 1 for x in either of the 2 given equations.