3x+4y=19 and 3x+6y=33 solve by elimination

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asked Sep 13, 2018 80.1k views

1 Answer

Kishikawa Katsumi · Answer 1 · 2018-09-18T08:35:33+0000

Just subtract the 1st equation from the 2nd, as follows:

3x+6y=33
-(3x+4y=19)
-----------------
2y= 14, and y = 7. Sub 7 for y in either of the original equations to obtain the value of x. Write your answer in the form (x, 7).

3x+4y=19 and 3x+6y=33 solve by elimination

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