Question

Wesley is traveling from California to Utah. His trip covers a distance of 673.1 miles. For the first 3 hours, he travels at an average speed of 67.2 miles per hour. For the next 2 hours, he travels at an average speed of 69.5 miles per hour. Wesley must travel miles farther before he reaches his destination. If Wesley travels at a fixed speed of 66.5 miles per hour during the final leg of the trip, it will take him another hours to get there. NextReset

Answer 1

it would take 5 more hours to travel the last 332.4 miles

I hope this helps

Answer 2

Wesley will take another 5 hours to cover final leg.

Explanation:

Distance between California to Utah is 673.10 miles.

Wesley covers a distance with 67.20 miles per hour in 3 hours, so distance covered will be = Speed × time

= 67.20×3 = 201.6 miles

For next 2 hours Wesley's average speed was 69.5 miles per hour.

So distance covered by him = 69.5 × 2 = 139 miles

Now remaining distance to cover by him = 673.10 - (201.60 + 139)

= 673.10 - 340.60 = 332.50 miles

Now Wesley covers this remaining distance 332.50 mile with the speed of 66.5 miles per hour.

So time taken to cover this distance =
`(Distance)/(Speed)=(332.50)/(66.5)`

Distance covered = 5 hours.

Therefore, time taken to cover this final leg will be 5 hours.