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Suppose tanΘ = 3/5 , and that Θ is in quadrant I. Find tan2Θ.

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tan 2 O = 2 tan O / (1 - tan^2 O)

= 3/5 / (1 - (3/5)^2)

= 3/5 * 25/16 = 15/16 Answer
User Hevski
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