32.6k views
2 votes
For the circle whose diameter has endpoints of (2, 0) and (4, 8), write the equation in general form.

2 Answers

4 votes

Answer:

x^2 + y^2 - 6x - 8y + 8 = 0

Explanation:

User Mark Levison
by
6.1k points
4 votes

find the midpoint which is (3,4)

find the radius which is sqrt(17)

equation becomes (x-3)^2 +(y-4)^2 = 17

User Sebkopf
by
6.7k points
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