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On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until the correct one appears.

On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-1
On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-1
On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-2
On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-3
User Andoctorey
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8.9k points

2 Answers

2 votes
(see attachment)

The third graph
y=-|x|+1 is the correct one, since the peak of the line is over the x-axis.
On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-1
User Shahkalpesh
by
7.7k points
4 votes

Answer: The correct option is 4.

Step-by-step explanation:

The given equation is,


y=-|x|+1

This is a form of a modulus function, therefore shape of graph is V.

The graph of |x| is a upward v-shaped graph lies on origin.


f(x)=|x+a|+b

Where a represents horizontal shift and b represents vertical shift.

If a>0, then graph of |x| shifts left side. If a<0, then graph of |x| shifts right side.

If b>0, then graph of |x| shifts upward. If b<0, then graph of |x| shifts right downward.

In the given function -|x| means reflection along the x-axis and addition of 1 means the graph will shift in upward direction as shown in below figure.

The other way to choose the correct option is, find the y-intercept.

Putting x=0 in given equation we get y=1. So, the y intercepts is (0,1) which is sown in last figure only.

Therefore, the option 4 is correct.

On a separate piece of graph paper, graph y = -|x| + 1; then click on the graph until-example-1
User Iam ByeBlogs
by
8.6k points

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