Question

How much heat is required to increase the temperature of 198.5 grams of water from 25.0 degrees Celsius to 88.5 degrees Celsius

Answer 1

Answer:

q=5.27x10^4 J

Step-by-step explanation:

q=M⋅C⋅ΔT

q=(198.5g)⋅(4.18)⋅(88.5−25.0)

M is the mass. C is the specific heat. ΔT is the final temperature minus the initial temperature (T2−T1)