Question

#1 pls thanks ;) . It’s so hard I hate it

Answer 1

Given:

`\begin{gathered} -a+3b-3c=2\ldots(1) \\ a-2b+3c=-4\ldots(2) \\ -a+2b-c=-2\ldots(3) \end{gathered}`

To find a,b,c:

Adding the equations (1) and (2) we get,

`b=-2`

Adding the equations (2) and (3) we get,

`\begin{gathered} 2c=-6 \\ c=-3 \end{gathered}`

Subtituting b= -2 and c= -3 in the equation (3) we get,

`\begin{gathered} -a+2(-2)-(-3)=-2 \\ -a-4+3=-2 \\ -a-1=-2 \\ -a=-1 \\ a=1 \end{gathered}`

Hence the solution is,

a = 1

b = -2

c = -3