In order for an integer to be divisible by 3 4 and 5, it has to be divisible by the least common multiple of the 3, which is 3*4*5 = 60. So, the problem is now "how many of the first 500 positive integers are divisible by 60?"
You can answer this question by setting up an inequality: in order for a number to be positive and a multiple of 60, it has to be equal to 60 * (an integer). So, if n is a positive integer, you have
60n ≤ 500... now solve for n by division
n ≤ 8.333
Now the question is "how many positive integers are less than (or equal to) 8.333?" Clearly, all the numbers 1-8 are less than 8.333 while 9 is too high. Therefore, you have 8 positive integers, which means there are 8 multiples of 60, which means there are 8 positive integers divisible by 3, 4 and 5 that are less than or equal to 500.