Question

Question 8 of 10You add 500 mL of water at 10°C to 100 mL of water at 70°C. What is themost likely final temperature of the mixture?A. 80°CΟ ΟB. 20°CC. 10°CD. 60°CSUBMIT

Answer 1

Given that the mass of water is m1 = 500 mL at temperature T1 = 10 degrees C.

The mass of water is m2 = 100 mL at temperature T2 = 70 degrees C

We have to find the final temperature of the water mixture.

The formula to find the final temperature of the mixture is

`T_f=((m1T1+m2T2))/((m1+m2))`

Substituting the values, the final temperature of the water will be

`\begin{gathered} T_f=((500*10)+(100*70))/((500+100)) \\ =20^(\circ)\text{ C} \end{gathered}`

Thus, option (b) is correct.