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A 60 kg student is standing motionless. Approximately how much force is the floor exerting on the student? A. 60 kg downward B.600 N upward C.600 N downward
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A 60 kg student is standing motionless. Approximately how much force is the floor exerting on the student?

A. 60 kg downward
B.600 N upward
C.600 N downward

User Hem
by
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1 Answer

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The normal force is equal in magnitude and opposite in direction to the weight of the student.
W = m · g = 60 kg · 10 m/s² = 600 N ( downward )
N = - 600 N
Answer:
B ) 600 N upward.
User Avijit Karmakar
by
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