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When 90 g of water is split by electrolysis (2H2O → 2H2 +O2) at STP, how many liters of oxygen gas will be collected?

Question 6 options:
44.8 L
22.4 L
56.0 L
67.2 L

2 Answers

1 vote

Answer:

56.0 L

Step-by-step explanation:

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User Nitsas
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If the molecular weight of water is 18g/mol, then the number of water molecule would be: 90g/ (18g/mol)= 5 moles.

In the reaction equation, 2 H2O molecules will result in 1 O2 molecule. Then, the amount of O2 formed would be: 5 moles * (1/2)= 2.5 moles.

In STP, an ideal gas will have 22.4 liters of volume per mol. Then, the volume of the oxygen formed would be: 2.5 moles * (22.4l/mol)= 56.0 L
User Daniel Wehner
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6.6k points