Question

REALLY NEED MATH MIDPOINT STUFF HELP

Point A is located at ​(4, 8)​ and point B is located at ​(14, 10)​ .

What point partitions the directed line segment ​ AB¯¯¯¯¯ ​ into a 1:3 ratio?

Answer 1

i don't know if it was right or not so please check it out later and
Call C (x,y) the point you need to find
AC=1\3AB
AC=(x-4,y-8)
AB=(10,2)
*x-4=10*1\3 then x=22\3
y-8=1\3*2 then y=26\3

Answer 2

The answer to this question would be: (6.5 , 8.5)

To answer this question, you need to determine the x and y distance of both point. From A point the distance would be:
X distance= 14-4= 10
Y distance= 10-8= 2

Making it into 1:3 ratio means that dividing the line into 4 parts then take 1 part from the point A, or 3 part from point B. From A point the distance would be 1/4 total distance
The location would be:
X= 4 + (10*1/4)= 6.5
Y= 8+ (2*1/4)= 8.5
(6.5 , 8.5)