Question

A sample of gas contains 6.25 × 10-3 mol in a 500.0 mL flask at 265°C. What is the pressure of the gas in kilopascals? Using the equation P=(nRT)/V

Answer 1

Hopefully this will help you.

Answer 2

`P =55.9kPa`

Step-by-step explanation:

Hello,

In this case, by using the ideal gas law, we obtain the pressure in atm as:

`P=(6.25x10^(-3)mol*(265+273.15)K*0.082(atm*L)/(molK) )/(0.5000L)=0.552atm`

Thus, in kPa it result:

`P=0.552atm*(101.325kPa)/(1atm) =55.9kPa`

Best regards.