Question

Suppose three fair dice are rolled. what is the probability that at most one six appears?

Answer 1

The probability of no six appearing is:

`((5)/(6))^(3)=0.5787`
The probability of exactly one six appearing is:

`3C1*(1)/(6)*((5)/(6))^(2)=0.347`
The events 'no six' and 'one six' are mutually exclusive, therefore the probability of no more than one six is given by:
0.5787 + 0.347 = 0.9257