Question

Find the area of the entire figure. 22 yd! 30 yd 64 yd

Answer 1

The area of the figure will be the area of the rectangle plus the area of the triangle, therefore:

For the rectangle:

`\begin{gathered} Ar=w\cdot l \\ where\colon \\ w=64 \\ l=30 \\ so\colon \\ Ar=30\cdot64=1920yd^2 \end{gathered}`

The area of the triangle is:

`\begin{gathered} At=(b\cdot h)/(2) \\ At=(64\cdot22)/(2) \\ At=704yd^2 \end{gathered}`

Therefore, the area is:

`\begin{gathered} A_{}=Ar+At \\ A=1920yd^2+704yd^2 \\ A=2624yd^2 \end{gathered}`