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10 votes
10 votes
Find the area of the entire figure. 22 yd! 30 yd 64 yd

User Alexufo
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1 Answer

15 votes
15 votes

The area of the figure will be the area of the rectangle plus the area of the triangle, therefore:

For the rectangle:


\begin{gathered} Ar=w\cdot l \\ where\colon \\ w=64 \\ l=30 \\ so\colon \\ Ar=30\cdot64=1920yd^2 \end{gathered}

The area of the triangle is:


\begin{gathered} At=(b\cdot h)/(2) \\ At=(64\cdot22)/(2) \\ At=704yd^2 \end{gathered}

Therefore, the area is:


\begin{gathered} A_{}=Ar+At \\ A=1920yd^2+704yd^2 \\ A=2624yd^2 \end{gathered}

User Abu Saad Papa
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