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(a-5)(a+5)=a^2-25

(x-88)(x+88)=x^2-88^2

A^2-B^2=(a-b)(B-A)

SOLVE FOR X

X^2-9=5(x-3)

(w+2)(w-5)=w^2-4

solve

x^2-11x=0 for x

The square of a number plus 3 times the number is equal to four . What is the number.

is b factorable

x^2+bx+12

x^2-3x+b

User Ozan
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6.4k points

1 Answer

2 votes
Okay so first off I do not know if any of these are completely correct, as well as I totally forgot how to solve the last two. Either way, this is what I got for them.
The first is true
The second would be true although -88 squared is 7744 and the equation equals -7744 which can not be obtained by a square number of negative times a negative is a positive number. The third is not true for you do have -a^2 and -b^2 but you also end up with aB as well as -bA. The fourth in decimal form would be.167 The fifth again in decimal form would be 1.732 Then the next would be 0. Finally, the next one would be .090 Again, I do not know how to solve the last two and I honestly do not know if anyone of these is correct.
User Danirod
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6.8k points
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