Question

In ​ kite PQRS ​, TQ=3 cm and TP=4 cm. What is SP ?

Answer 1

Answer:The answer is 5

Explanation:

Answer 2

Answer: SP=5 cm

Explanation:

Since, Here PQRS is a kite where PR and SQ are the diagonals of the kite.

Let, PR is the major diagonal of the kite PQRS.

And let T is the intersection point of the diagonals.

Thus by the property of the kite diagonal PR bisect SQ with right angle.

⇒
`\angle QTP=90^(\circ)`

Therefore,
`PQ=√(TP^2+TQ^2)`

⇒
`PQ=√(4^2+3^2)`=
`√(25) =5` ( we can not take the negative value of root)

But, PQ=SP

Therefore, SP= 5 cm

Note: If we take SQ as the major diagonal then we also get the same result.