Question

What are the possible values of 'a' given that "a' is the integer of -1

Answer 1

Explanation:

olution: Let [math] n^2 +96 =x^2 [/math] where x and n are positive integers. Hence [math] 96= x^2 -n^2 =(x+n)(x-n) [/math]. Now [math] (x+n) + (x-n) =2x ...

Answer 2

Let's evaluate the possibilities.

First, an integer number is a whole number (not a fractional number) that can be positive, negative, or zero. So, -3, -2, ... 0, 3, 4..

-1 < a ≤ 2​, means:

As we can see, a can be 0, 1 or 2.

The symbol ≤ means that a is lesser or equal to 2, while the symbol < means that 1 is lesser than a, but a is not included.

So, the answer is: "a" = 0, 1 or 2. Which can also be represented in a set S = {0, 1, 2}.