Question

K+a=500
3k+10a=3,600
find k and a using elimination plss helppp

Answer 1

a=300 and k=200

Explanation:

Multiply the first equation by -10,and multiply the second equation by 1.

−10(a+k=500)

1(10a+3k=3600)

Becomes:

−10a−10k=−5000

10a+3k=3600

Add these equations to eliminate a:

−7k=−1400

Then solve−7k=−1400for k:

−7k=−1400 (Divide both sides by -7)

`(-7k)/(-7) =(-1400)/(-7)`

Now that we've found k let's plug it back in to solve for a.

Write down an original equation:

a+k=500

Substitute200forkina+k=500:

a+200=500

a+200+−200=500+−200(Add -200 to both sides)

a=300

Hope this helps :)