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A ball is thrown in the air from the top of a building. its height, in meters above ground as a function of time, in seconds, is given by h ( t ) = − 4.9 t 2 + 29 t + 18 h(t)=-4.9t2+29t+18. how long does it take to reach maximum height? round to the nearest hundredth of a second.

User Henry B
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2 Answers

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Final answer:

The ball takes approximately 2.96 seconds to reach its maximum height.

Step-by-step explanation:

The maximum height of the ball can be determined by finding the vertex of the parabolic function given by the equation h(t) = -4.9t^2 + 29t + 18. The vertex of a parabola is given by the formula t = -b/2a, where a, b, and c are the coefficients of the quadratic equation. In this case, a = -4.9 and b = 29. Plugging these values into the formula gives:

t = -29 / (2 * -4.9) = 2.96

Therefore, it takes approximately 2.96 seconds for the ball to reach its maximum height.

User Kashalo
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So you have to multiply the numbers inside the parentheses then divide what you get and then after that you’re going to multiply your answer and then get your answer than divided it then after that answer you at eight and then you then
User NuSphere
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