Question

How many protons, electrons, and neutrons does the following Isotope contain?
27Al 3+

Answer 1

The isotope 27Al 3+ contains 13 protons, 10 electrons due to the 3+ charge indicating the loss of three electrons, and 14 neutrons calculated by subtracting the number of protons from the isotope's mass number (27 - 13).

Step-by-step explanation:

The given isotope is Aluminum (Al) with a mass number of 27 and a charge of 3+. The number of protons in an atom is identified by its atomic number, which for aluminum is 13 (you can find this on the periodic table). Since this is an ion with a 3+ charge, it means the atom has lost three electrons. Therefore, the number of electrons in this Al3+ ion is 10 (13 protons - 3+ charge = 10 electrons). The mass number of an isotope equals the sum of its protons and neutrons, so to find the number of neutrons we subtract the atomic number (number of protons) from the mass number: 27 - 13 = 14 neutrons.

So, the aluminum isotope 27Al 3+ contains 13 protons, 10 electrons, and 14 neutrons.

Answer 2

Answer: Since the mass (27) is equal to number of protons + number of neutrons, then number of neutrons = 27 - 13 = 14. 3.

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