Question

1. Find the first 6 terms of (a^)n = 5n-2

Answer 1

Given the following expression for a sequence:

`a_n=5n-2`

we can find the first 6 terms by solving for n =1,2,3,4,5 and 6:

`\begin{gathered} n=1 \\ \Rightarrow a_1=5\cdot1-2=5-2=3 \\ n=2 \\ \Rightarrow a_2=5\cdot2-2=10-2=8 \\ n=3 \\ \Rightarrow a_3=5\cdot3-2=15-2=13 \\ n=4 \\ \Rightarrow a_4=5\cdot4-2=20-2=18 \\ n=5 \\ \Rightarrow a_5=5\cdot5-2=25-2=23 \\ n=6 \\ \Rightarrow a_6=5\cdot6-2=30-2=28 \end{gathered}`

therefore, the first 6 terms are 3, 8, 13, 18, 23 and 28