Question

`h(t) = 8 + 40.8t -{16t}^(2)`
at what height is the ball after 2 seconds?​

Answer 1

`h(t) = 8 + 40.8t - {16t}^(2) \\ h(2) = 8 + 40.8(2) - 16 {(2)}^(2) \\ = 8+81.6 - 64 \\ = 89.6 - 64 = \boxed{25.6}`

After 2 seconds the ball will be at the height of 25.6 unit.

Answer 2

Explanation:

When t = 2,

h(2) = 8 + 40.8(2) - 16(2)² = 8 + 81.6 - 64 = 25.6

Therefore the height after 2 sec is 25.6.