Question

Two trains leave towns 1160 kilometers apart at the same time and travel toward each other. One train travels 22 faster than the other. If they meet in 4 hours, what is the rate of each train? h

Answer 1

Distance = rate x time

x= rate of slower train

x+22 = rate of faster train

Both trains meet when the sum of the distances is 1160 km.

4x+ 4 (x+22) = 1160

Solve for x:

4x+4x+88 = 1160

8x = 1160-88

8x = 1072

x= 1072/8

x= 134

rate of slower train = 134 km /h

Rate of faster train= x+22 = 134+22 = 156 km/h