Question

Please solve for b.

Answer 1

For this one.

`-(9)/(3)+b=-1 \ \textgreater \ \mathrm{Divide\:the\:numbers:}\:(9)/(3)=3 \ \textgreater \ -3+b=-1`


`\mathrm{Add\:}3\mathrm{\:to\:both\:sides} \ \textgreater \ -3+b+3=-1+3 \ \textgreater \ Simplify \ \textgreater \ b=2`

Hope this helps!