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How many milliliters of the 0.5% solution must be added to the 2% solution to get a 0.65% solution?

2 Answers

4 votes

Final answer:

To solve the problem, use the equation (concentration of solution A)(volume of solution A) + (concentration of solution B)(volume of solution B) = (concentration of final solution)(total volume of final solution). Plug in the given values, then simplify and solve the equation to find the relationship between the volume of solution B and the total volume of the final solution.

Step-by-step explanation:

To solve this problem, we can use the equation:

(concentration of solution A)(volume of solution A) + (concentration of solution B)(volume of solution B) = (concentration of final solution)(total volume of final solution)

Let's use the given information:

  • Concentration of solution A (0.5%)
  • Concentration of solution B (2%)
  • Concentration of final solution (0.65%)
  • Volume of solution B (unknown, represented as x)
  • Total volume of final solution (unknown, represented as y)

Plugging in the values into the equation, we have:

(0.005)(x) + (0.02)(y - x) = (0.0065)(y)

Simplifying and solving the equation gives us:

0.005x + 0.02y - 0.02x = 0.0065y

0.0165y - 0.015x = 0.005x

0.0115y = 0.02x

0.023y = 2x

23y = 200x

To solve for y, we can choose a value for x (the volume of solution B) and find the corresponding value for y (the total volume of the final solution).

User Aprameyo Roy
by
8.7k points
4 votes
whats the attachemnt 
User Volodymyr Sorokin
by
8.8k points

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