In thia problem we have that
m<1 and m< 2 are consecutive interior angles
that means
m<1+m<2=180 ------> supplementary angles
substitute the given values
4x+16+2x-22=180
solve for x
6x-6=180
6x=180+6
6x=186
x=31
Find the value of m<1
m<1=4(31)+16
m<1=140 degrees