Question

Given: ABC and FGH are right angles; BA||GF; BC ≅ GH Prove: ABC ≅ FGH Step 1: We know that ABC ≅ FGH because all right angles are congruent. Step 2: We know that BAC ≅ GFH because corresponding angles of parallel lines are congruent. Step 3: We know that BC ≅ GH because it is given. Step 4: ABC ≅ FGH because of the

Answer 1

B. AAS congruence theorem

Explanation:

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Answer 2

Explanation:

Given: ΔABC and ΔFGH are right angles, BA||GF; BC ≅ GH.

To prove: ΔABC ≅ ΔFGH

Proof:

Step 1. ∠ABC ≅ ∠FGH (Because all right angles are congruent)

Step 2. ∠BAC ≅ ∠GFH (Because corresponding angles of parallel lines are congruent)

Step 3. BC ≅ GH (Given)

Step 4. From ΔABC and ΔFGH

∠ABC ≅ ∠FGH

BC ≅ GH

∠BAC ≅ ∠GFH

thus, by ASA rule of congruency, ΔABC ≅ ΔFGH.