Answer:
The best option that represents the relationship between the years x and the annual salary in thousand of dollar f (x) is f(x)=70*1.17^x (first option)
Explanation:
An increment function can be expressed as the initial value A times, the increment rate r raised to the amount of time x:
f(x)=A.r^x
In this particular case, the initial value is the initial salary in 2005 and the amount of time will be the years.
The annual increment rate of the salary can be found by the rate of the salary in 2006 and the salary of 2005:
r=82000/70000=1.17
Replacing the initial salary in thousands of dollars:
f(x)=70.1.17^x