Question

HELP
In ΔSTU, SU = 18 and TU = 13. Find m∠T to the nearest tenth of a degree.

Answer 1

Measure of ∠T = 54.2°

Explanation:

In the given triangle STU, SU = 18 and TU = 13.

We have to find the measure of angle T.

Since tanT =
`(Height)/(Base)`

tanT =
`(SU)/(TU)`

tanT =
`(18)/(13)`

∠T =
`tan^(-1)(1.3846)`

∠T = 54.16 ≈ 54.2°

Answer 2

angle T = arctan(18/13)

= 54.16 = 54.2 degrees