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What was the percent of atmospheric co2 in 1850 if it was 280 ppm? move the decimal place 4 digits to the left to get percent (%)?

2 Answers

5 votes

Answer: 0.028

Step-by-step explanation:

ppm is defined as the mass of the solute present in one million
10^6 parts by mass of the solution.

percent is defined the the mass of the solute present in hundred parts by mass of the solution.


ppm=\frac{\text {mass of solute}}{\text {mass of solution}}* 10^6

Given: Atmospheric
CO_2 = 280 ppm


10^6 parts contain 280 parts

100 parts will contain =
(280)/(10^6)* 100 = 0.028

Thus the percent of atmospheric
CO_2 is 0.028.

User Fraser Graham
by
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4 votes
We know that the atmospheric co2 in 1850 was 280 parts per million. Thus we have that the percentage is 280/1 million * 10000 . Thus we have that the percent of atmospheric co2 in 1850 was 2.8%
User Steve Padmore
by
6.8k points
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